16^2x-7=1/5^5x+2

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Solution for 16^2x-7=1/5^5x+2 equation:



16^2x-7=1/5^5x+2
We move all terms to the left:
16^2x-7-(1/5^5x+2)=0
Domain of the equation: 5^5x+2)!=0
x∈R
We get rid of parentheses
16^2x-1/5^5x-2-7=0
We multiply all the terms by the denominator
16^2x*5^5x-2*5^5x-7*5^5x-1=0
Wy multiply elements
80x^7-10x^5-35x^5-1=0
We do not support expression: x^7

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